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In an ap a 1 an 20 sn 399

WebSep 20, 2024 · Given : The first term of an A.P. is 1 and the nth term is 20. If Sn = 399 To find : The value of n ? Solution : The sum of n terms of A.P is given by, Where, a is the first term a=1 l is the nth term l=20 =399 is the sum of n terms Substitute the value in the formula, Therefore, the value of n is 38. #Learn more WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : If an A.P. has a = 1, t. n. = 20 and s. n. = 399, then value of n is : A. 20. B. 32. C. 38.

If an AP has a=1, an=20 and Sn=399, then find the value of n.

WebSolution: An arithmetic progression (AP) is a sequence where the two consecutive terms have the same common difference. It is obtained by adding the same fixed number to its previous term. The nth term of an AP is. aₙ = a + (n - 1 )d. a = first term. aₙ = nth term. d = common difference. Considering the question, we get the value as, WebMar 28, 2024 · Objectives: This study aims to investigate the risk factors associated with severity and death from COVID-19 through a systematic review and meta-analysis of the published documents in Iran.Methods: A systematic search was performed based on all articles indexed in Scopus, Embase, Web of Science (WOS), PubMed, and Google Scholar … aldi mobile refund https://emmainghamtravel.com

In an A.P. Given a = 3, n = 8, S = 192, find ‘d’. from Mathematics ...

WebMar 11, 2024 · answered In an Ap, a=1, an=20, sn=399 then find n Advertisement Answer 3 people found it helpful pragyanrana31 Answer: Sn=n/2 (a+l) . . 399=n/2 (1+20) . . 399*2/21=n . . 19*2=n . . N=38 . . Hope this helps you . . Pls mark Brainliest answer! ️ Find Math textbook solutions? Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 … WebBesides giving the explanation of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.?, a detailed solution for In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? … WebÿØÿî AdobedÀ ÿÛ„ ÿÀ € ÿÄØ ! aldi mobile recharge ch

In an A.P. , if a = 1, an= 20 and sn =399, then n is? - Meritnation

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In an ap a 1 an 20 sn 399

If an AP has a = 1 , tn = 20 and Sn = 399 , then the value of …

WebOct 25, 2015 · In an AP, if a=1,an=20 and Sn= 399, then n=? Advertisement Expert-Verified Answer 603 people found it helpful Brainly User since , an = a+ (n-1)d 20 = 1 + (n-1)d 19 = … WebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 d)19 - Maths - Arithmetic Progressions

In an ap a 1 an 20 sn 399

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WebIn an AP, if a = 1, an = 20 and Sn = 399, then n is equal to (a) 19 (b) 21 (c) 38 (d) 42 Solution: Question 18: The sum of first five multiples of 3 is (a) 45 (b) 55 (c) 65 (d) 75 Solution: (a) The first five multiples of 3 are 3, 6, 9,12 and 15. Here, first term, a = 3, common difference, d = 6-3 = 3 and number of terms, n = 5 WebAug 25, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. ← Prev Question Next Question →. 0 votes. 17.2k views. asked Aug 25, 2024 in …

WebSum of n terms of AP is given by: S n = n 2 2 a 1 + n-1 d where a 1 = first term, d = common difference. S 24-4 = 24-4 2 2 × 1 + 24-4-1 13 ∵ d = 13, n = 24, a 1 = 1 S 20 = 20 2 2 + 19 × 13 = 2490. a n-4 = a 1 + n-4-1 d a 24-4 = 1 + 24-4-1 13 ∵ d = 13, n = 24, a 1 = 1 a 20 = 248. Therefore, the ordered pair S n-4, a n-4 is equal to (2490 ...

WebHere d = 19 – 20 = (–1) and S n = 200 Hence, the required number of rows are 16 and in the top row there are 5 logs. 224 Views. Answer . The sum of the third and the seventh terms of an AP is 6 and their product is 8. Find the sum of first sixteen terms of the AP. Let the first term and the common difference of the A .P. be a and d ... WebFeb 11, 2013 · if an ap a=1 ,an=20,sn= 399 then n is Asked by anish mishra 11 Feb, 2013, 02:45: PM Expert Answer Sn=399 => n/2 (a + an) = 399 => n/2 ( 1 + 20) = 399 =>n/2 (21) = 399 => n = 399 X 2/21 => n= 38 Answered by 11 Feb, 2013, 05:49: PM Application Videos This video explains the concept of Arithmetic Progression, Solving Linear E...

WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : A. 20 B. 32 C. 38 D. 40 Answer: Option C Solution (By Examveda Team) S n = 1 2 ( a + l) × n ⇒ 399 = ( 1 + 20) × n 2 ⇒ 399 × 2 = 21 × n ⇒ n = 399 × 2 21 ⇒ n = 19 × 2 ⇒ n = 38 Join The Discussion Related Questions on Progressions How many terms are there in 20, 25, 30 . . . . . . 140?

WebJan 23, 2024 · In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42. 2Pi classes. 36.7K subscribers. aldi mobile reset passwordWebFeb 22, 2013 · In an A.P. , if a = 1, an= 20 and sn =399, then n is? Share with your friends 1 Follow 0 Jai Prakash, added an answer, on 22/2/13 we know from that formula that, Sn = n/2 (a + an) 399 = n/2 (1 + 20) 399*2 = n (21) n = 798/21 = 38 Therefore n = 38 Was this answer helpful? 3 View Full Answer aldimobile registerWebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 - Maths - Arithmetic Progressions - 1833845 Meritnation.com Class-10 » Maths Arithmetic … aldi mobile rolloverWebAnswer : Let the required numbers in A.P.are (a - d), a and (a + d). Sum of these numbers = (a - d) + a + (a + d) = 3a Product of these numbers = (a - d)× a × (a + d)=a (a 2 - d 2) But given, sum = 24 and product = 440 ∴ 3a = 24 a = 8 and a (a 2 - d 2) = 8 (64 - d 2) = 440 [ a = 8] Or, 64 - d 2 = 55 Or, d 2 = 64 - 55 => d 2 = 9 => d = ± 3 aldi mobile roaming chargesWeb20．（本小题满分14分）已知等差数列 an 的公差d 0，它的前n项和为Sn，若 ... 8 Sn . y2. 1的左、右两个顶点分别为A、B．曲21．（本小题满分14分）已知椭圆x 4. 2. 线C是以A、B. P在第一象限且在曲线C上，直线AP与椭圆相交于另一点T． （1）求曲线C的方程； ... aldi mobile rollover dataWebFeb 14, 2024 · Solution For (2) In an AP if a=1,an =20, and Sn =399,0 then n is equal a=1an =20Sn =399 aldi mobile roaming internationalWebIf in an AP a = 1, t n = 20 and Sn = 399 then n is (a) 19 (b) 21 (c) 38 (d) 42 Report 497 Share Follow Answer peter Reputation: 2.6K University of Lagos, Nigeria 30 July 2024 … aldi mobile reviews australia